1.7 Intermediate Value Theoremap Calculus



In this section we learn a theoretically important existence theorem called theIntermediate Value Theorem and we investigate some applications.

Solved: Apply the Intermediate Value Theorem to f(x) = 7x - cos 9x on 0, 1, evaluate f(0) and f(1). (Round your answers to two decimal places.). For Teachers for Schools for Working Scholars. X Exclude words from your search Put - in front of a word you want to leave out. For example, jaguar speed -car Search for an exact match Put a word or phrase inside quotes.

Intermediate Value Theorem

In this section we discuss an important theorem related to continuous functions.Before we present the theorem, lets consider two real life situations and observe animportant difference in their behavior. First, consider the ambient temperature andsecond, consider the amount of money in a bank account.

First, suppose that the temperature is at 8am and then suppose it is at noon.Because of the continuous nature of temperature variation, we can be surethat at some time between 8am and noon the temperature was exactly .Can we make a similar claim about money in a bank account? Supposethe account has $65 in it at 8am and then it has $75 in it at noon. Did ithave exactly $70 in it at some time between 8 am and noon? We cannotanswer that question with any certainty from the given information. On onehand, it is possible that a $10 deposit was made at 11am and so the total inthe bank would have jumped from $65 dollars to $75 without ever beingexactly $70. On the other hand, it is possible that the $10 was added in $5increments. In this case, the account did have exactly $70 in it at some time. Thefundamental reason why we can make certain conclusions in the first casebut cannot in the second, is that temperature varies continuously, whereasmoney in a bank account does not (it will have jump discontinuities). When aquantity is known to vary continuously, then if the quantity is observed to havedifferent values at different times then we can conclude that the quantitytook on any given value between these two at some time between our twoobservations. Mathematically, this property is stated in the Intermediate ValueTheorem.

Intermediate Value Theorem

If the function is continuous on the closed interval and is a number between and ,then the equation has a solution in the open interval .

The value in the theorem is called an intermediate value for the function on theinterval . Note that if a function is not continuous on an interval, then the equation may or may not have a solution on the interval.

Remark: saying that has a solution in is equivalent to saying that there exists anumber between and such that .

The following figure illustrates the IVT.

example 1 Show that the equation has a solution between and .
First, the function is continuous on the interval since is a polynomial. Second,observe that and so that 10 is an intermediate value, i.e., Now we can apply theIntermediate Value Theorem to conclude that the equation has a least one solutionbetween and . In this example, the number 10 is playing the role of in the statementof the theorem.
(problem 1) Determine whether the IVT can be used to show that the equation has asolution in the open interval .

Is continuous on the closed interval ?

and

Is an intermediate value?

YesNo

Can we apply the IVT to conclude that the equation has a solution in the openinterval ?

example 2 Show that the equation has a solution between and .

First, note that the function is continuous on the interval and hence it iscontinuous on the sub-interval, . Next, observe that and so that 2 is anintermediate value, i.e., Finally, by the Intermediate Value Theorem wecan conclude that the equation has a solution on the open interval . Inthis example, the number 2 is playing the role of in the statement of thetheorem.

(problem 2) Determine whether the IVT can be used to show that the equation has a solution in the open interval Is continuous on the closed interval ?

1.7 Intermediate Value Theoremap Calculus 2nd Edition

and

Is an intermendiate value?

YesNo

Does the IVT imply that the equation has a solution in the open interval ?

example 3 Show that the function has a root in the open interval .

Recall that a root occurs when . Since is a polynomial, it is continuous on theinterval . Plugging in the endpoints shows that 0 is an intermediate value: and so By the IVT, we can conclude that the equation has a solution (and hence has aroot) on the open interval .

Intermediate Value Theorem Examples

(problem 3) Determine whether the IVT can be used to show that the function has aroot in the open interval .

Is continuous on the closed interval ?

and

Is an intermendiate value?

YesNo

Does the IVT imply that the function has a root in the open interval ?

example 4 Show that the equation has a solution between and .
Note that the equation is equivalent to the equation . The latter is the prefered formfor using the IVT. So let Since is the difference between two continuous functions, itis continuous on the closed interval . Next, we compute and and show that 0 is anintermediate value: and and so, By the IVT, the equation has a solution in theopen interval . Hence the equivalent equation has a solution on the sameinterval.
1.7 Intermediate Value Theoremap Calculus
example 5 Use the IVT four times to approximate a root of the polynomial First, isa polynomial, so it is continuous on any closed interval. Next, note that By the IVT has a root in the interval . To use the IVT a second time, we now determine themidpoint of this interval: and we plug this in to : Combining this with we can usethe IVT again to conclude that has a root on the interval . This intervalis half of the original interval- the original interval has been bisected. Wenow use the IVT a third time. The midpoint of the interval is . We plugthis into : Combining this with we can use the IVT to conclude that hasa root on the interval . This interval is half of the previous interval- theprevious interval has been bisected. We will do this a fourth and final time.Note that is the midpoint of the interval and Combining this with wecan use the IVT a fourth time to conclude that has a root on the interval. At this stage, our approximation of the root is which is the midpointof this interval. Our error is then no more than , which is half the widthof the interval. We will stop here, but the method could theoretically becontinued indefinitely giving a better approximation to the root each time.This method of approximating roots is called the Method of ContinuedBisection.
Here is a detailed, lecture style video on the Intermediate Value Theorem:

All textbook readings are from:

Apostol, Tom M. Calculus, Volume 1: One-Variable Calculus, with An Introduction to Linear Algebra. Waltham, Mass: Blaisdell, 1967. ISBN: 9780471000051.

Additional course notes by James Raymond Munkres, Professor of Mathematics, Emeritus, are also provided.

Mean Value Theorem

Course readings.
SES #TOPICSTEXTBOOK READINGSCOURSE NOTES READINGS
Real numbers
0Proof writing and set theoryI 2.1-2.4
1Axioms for the real numbersI 3.1-3.7
2Integers, induction, sigma notationI 4.1-4.6Course Notes A
3Least upper bound, triangle inequalityI 3.8-3.10, I 4.8Course Notes B
4Functions, area axioms1.2-1.10
The integral
5Definition of the integral1.12-1.17
6Properties of the integral, Riemann conditionCourse Notes C
7Proofs of integral properties88-90, 113-114Course Notes D
8Piecewise, monotonic functions1.20-1.21Course Notes E
Limits and continuity
9Limits and continuity defined3.1-3.4Course Notes F
10Proofs of limit theorems, continuity3.5-3.7
11Hour exam I
12Intermediate value theorem3.9-3.11
13Inverse functions3.12-3.14Course Notes G
14Extreme value theorem and uniform continuity3.16-3.18Course Notes H
Derivatives
15Definition of the derivative4.3-4.4, 4.7-4.8
16Composite and inverse functions4.10, 6.20Course Notes I
17Mean value theorem, curve sketching4.13-4.18
18Fundamental theorem of calculus5.1-5.3Course Notes K
19Trigonometric functionsCourse Notes L
Elementary functions; integration techniques
20Logs and exponentials6.3-6.7, 6.12-6.16Course Notes M
21IBP and substitution5.7, 5.9Course Notes N
22Inverse trig; trig substitution6.21
23Hour exam II
24Partial fractions6.23Course Notes N
Taylor's formula and limits
25Taylor's formula7.1-7.2
26Proof of Taylor's formulaCourse Notes O
27L'Hopital's rule and infinite limits7.12-7.16Course Notes P
Infinite series
28Sequences and series; geometric series10.1-10.6, 10.8 (first page only)
29Absolute convergence, integral test10.11, 10.13, 10.18
30Tests: comparison, root, ratio10.12, 10.15Course Notes Q
31Hour exam III
32Alternating series; improper integrals10.17, 10.23
Series of functions
33Sequences of functions, convergence11.1-11.2
34Power series11.3-11.4Course Notes R
35Properties of power seriesCourse Notes R
36Taylor series11.9Course Notes S
37Fourier seriesCourse Notes T

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Extreme Value Theorem

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